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(C) The oxidizing power of a halogen is determined by the standard electrode potential $(E^{\circ})$,which depends on three factors: enthalpy of disso

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Hydration enthalpy

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(C) The oxidizing power of a halogen is determined by the standard electrode potential $(E^{\circ})$,which depends on three factors: enthalpy of dissociation,enthalpy of electron gain,and enthalpy of hydration. Fluorine is the strongest oxidizing agent because its low bond dissociation energy and very high negative hydration enthalpy significantly outweigh its relatively low electron gain enthalpy compared to chlorine.

Which among the following factors is the most important in making fluorine the strongest oxidising halogen?

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